Re: Brain Teaser and a request of all of you: -
Kathy - 12-12-2013
(12-11-2013, 12:49 PM)washington.is.money link Wrote:I, too, have an answer. Unlike my compatriots, I am unburdened by the fear of being wrong in public. (I am a journalist.)
>:(Â Time to get out the pica pole for a smackdown.
Re: Brain Teaser and a request of all of you: -
washingtonismoney - 12-12-2013
(12-12-2013, 09:29 AM)Kathy link Wrote:>:(Â Time to get out the pica pole for a smackdown.
Being wrong in public is bad, obviously. And I wouldn't want any errors that bespeak an obvious lack of ethics, competence, or ability. But fundamentally if you're going to write in public you're going to have to get over any stage fright you might have and say what you think.
Re: Brain Teaser and a request of all of you: -
stupac2 - 12-12-2013
(12-12-2013, 09:44 AM)washingtonismoney link Wrote:Being wrong in public is bad, obviously. And I wouldn't want any errors that bespeak an obvious lack of ethics, competence, or ability. But fundamentally if you're going to write in public you're going to have to get over any stage fright you might have and say what you think.
Alternatively, you have to be prepared to deny to the death that you were ever actually wrong. Which seems to be an increasingly popular way to go about it these days among the talking-head pundit class. We can only hope it never infects the real journalists.
Re: Brain Teaser and a request of all of you: - welcher232 - 12-12-2013
I get 8 = 168 (typo first time), and 9 = 369, but I just can't come up with 10. Part of me think's there is no solution because 1 would also be undefined in this group.
Re: Brain Teaser and a request of all of you: -
CompSci87 - 12-13-2013
(12-12-2013, 10:42 PM)welcher232 link Wrote:I get 8 = 168 (typo first time), and 9 = 369, but I just can't come up with 10. Part of me think's there is no solution because 1 would also be undefined in this group.
I have no clue where you got those values. Care to explain? The values given in the original puzzle fit the pattern n "=" 2n[sup]2[/sup].
Re: Brain Teaser and a request of all of you: - welcher232 - 12-13-2013
I used the construct that 99.9% of people wouldn't be able to get it. I could just be way over analyzing, and looking for a pattern that isn't really there... here goes.
I drop the last digit of each number, and multiply the remaining digit by N. That number is added to the series N*5.
3=18Â (3*1) + (3*5) = 18
4=32Â (4*3) + (4*5) = 32
5=50Â (5*5) + (5*5) = 50
6=72Â (6*7) + (5*6) = 72
7=98Â (7*9) + (5*7) = 98
8=168 (8*16) + (5*8) = 168
9=369 (9*36) + (9*5) = 369
Like I said, I was purposefully looking for something that might not even actually be there.
Re: Brain Teaser and a request of all of you: -
TriangleTree - 12-13-2013
(12-13-2013, 12:37 AM)welcher232 link Wrote:I used the construct that 99.9% of people wouldn't be able to get it. I could just be way over analyzing, and looking for a pattern that isn't really there... here goes.
I drop the last digit of each number, and multiply the remaining digit by N. That number is added to the series N*5.
3=18Â (3*1) + (3*5) = 18
4=32Â (4*3) + (4*5) = 32
5=50Â (5*5) + (5*5) = 50
6=72Â (6*7) + (5*6) = 72
7=98Â (7*9) + (5*7) = 98
8=168 (8*16) + (5*8) = 168
9=369 (9*36) + (9*5) = 369
Like I said, I was purposefully looking for something that might not even actually be there.
Welcher, your numbers do work through 7, but that's a coincidence of the tens digit increasing by 2 each time in 2n^2 through 7 (
18,
32,
50,
72,
98.)Â
Looking at your numbers, the pattern that you actually found, n*(1+2(n-3))+5n, also works to be 2N^2:
=n*(1+2n-6)+5n
=n+2n^2-6n+5n
=2n^2
Can I get a free angry nerds t-shirt now?
Re: Brain Teaser and a request of all of you: - welcher232 - 12-13-2013
Like I said, I realize the common response (and right response) was going to be 2n^2. You could find a many patterns with such a small subset of numbers. I figured it was a trick question, and I was going for the gusto.
Per my example 8, and 9 also work.